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Consider the decomposition of N2O5(g) to form NO2(g) and O2(g) . At a particular instant N2O5 disappears at a rate of 2.5 x 10-2 mol dm-3 s-1 . At what rates are NO2 and O2 formed? What is the rate of the reaction?

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Best answer

2N2O5(g) → 4NO2(g) + O2(g)

from the stoichiometry of the reaction.

Rate of disappearance of N2O5 is 2.5 x 10-2 mol dm-3s-1

∴ The rate of formation of NO2 at this temperature is 2 x 2.5 x 10-2 = 5 x 10-2 mol dm-3 s-1

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