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Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below:

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Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below:

Then the species undergoing disproportional is .....

(a) Br2 

(b) BrO-4 

(c) BrO-3 

(d) HBrO

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(d) HBrO

(Ecell)A  = – 1.82 + 1.5 = – 0.32V 

(E ​​​​​​cell)B = – 1.5 + 1.595 = + 0.095V 

(Ecell)C = 1.595 + 1.0652 = – 0.529V 

The species undergoing disproportionation is HBrO

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