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Solve for x, the inequalities in 4x + 3 ≥ 2x + 17, 3x – 5 < – 2.

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 Solve for x, the inequalities in 4x + 3 ≥ 2x + 17, 3x – 5 < – 2.

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According to the question,

4x + 3 ≥ 2x + 17

⇒ 4x – 2x ≥ 17 – 3

⇒ 2x ≥ 14

⇒ x ≥ 7 …(i)

Also,

3x – 5 < – 2

⇒ 3x < 3

⇒ x < 1 …(2)

Since, equations [i] and [ii] cannot be possible simultaneously,

We conclude that x has no solution.

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