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The slope at any point of a curve y = f (x) is given by (dy/dx) = 3x^2 and it passes through (-1, 1). Then the equation of the curve is

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The slope at any point of a curve y = f (x) is given by (dy/dx) = 3x2 and it passes through (-1, 1). Then the equation of the curve is …

(a) y = x3 + 2 

(b) y = 3x2 + 4 

(c) y = 3x3 + 4 

(d) y = x3 + 5

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Answer is (a) y = x3 + 2

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