The point (1, 2) lies inside the circle x^2 + y^2 – 2x + 6y + 1 = 0.

Question

State whether the statements True or False. Justify

The point (1, 2) lies inside the circle x² + y² – 2x + 6y + 1 = 0.

Answer 1

Putting the values, in the given equation,

x² + y² - 2x + 6y + 1 = 0

1² + 2² - 2 (1) + 6 (2) + 1

1 + 4 – 2 + 12 + 1

= 16 > 0

So the point lies outside the circle.

FALSE