Question

Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated ? 

(1) 2!3!4! 

(2) (3!)³.(4!) 

(3) (3!)².(4!) 

(4) 3!(4!)³

Answer 1

Total numbers in three families = 3 + 3 + 4 = 10

So total arrangement = 10!

So option(2) is correct.