Question

Area (in sq. units) of the region outside \(\frac{|x|}{2}+\frac{|y|}{3} = 1\) and inside the ellipse \(\frac{x^2}{4}+\frac{y^2}{9}=1\) is :

(1) 3 (4 - π)

(2) 6 (π - 2)

(3) 3 (π - 2)

(4) 6 (4 - π)

Answer 1

Answer is (2) 6 (π - 2)

Area of Ellipse = πab = 6π

Required area,

= π × 2 × 3 – (Area of quadrilateral)