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The number of protons, neutrons and electrons in ^175_71Lu , respectively, are : (1) 175, 104 and 71 (2) 71, 104 and 71

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The number of protons, neutrons and electrons in \(^{175}_{71}\)Lu , respectively, are : 

(1) 175, 104 and 71 

(2) 71, 104 and 71 

(3) 104, 71 and 71 

(4) 71, 71 and 104

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1 Answer

+1 vote
by (48.4k points)

(2) 71, 104 and 71 

\(^{175}_{71}\)Lu

p+ = 71 

n0 = 175 – 71 = 104 

e– = 71

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