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in Sets, Relations and Functions by (47.2k points)
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The function f: [0, 2π] ➝ [-1, 1] defined by f(x) = sin x is 

(a) One to one 

(b) Onto 

(c) Bijection 

(d) Cannot be defined

1 Answer

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by (49.3k points)
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Best answer

(b) Onto

For x = π/4, x = 3π/4, f(x) = 1/√2

So it is not one-to-one 

So it is an onto function

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