Question

Determine the region in the plane determined by the inequalities:

x ≤ 3y, x ≥ y

Answer 1

Given in equation are x ≤ 3y,x ≥ y 

Suppose x = 3y ⇒ x/3 = y

x	0	3	6	-3
y	0	1	2	-1

If x = y

x	1	2	-1	-2
y	1	2	-1	-2