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in Trigonometry by (49.0k points)
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If tan–1 x + tan–1 y = 4π/5, then cot–1x + cot–1 y equals

A. π/5

B. 2π/5

C. 3π/5

D. π

1 Answer

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by (50.4k points)
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Best answer

We know that,

We have,

tan–1 x + tan–1 y = 4π/5 … (1)

Let, cot–1x + cot–1 y = k … (2)

Adding (1) and (2) –

Now, tan–1 A + cot–1 A = π/2 for all real numbers.

So, (tan–1 x + cot–1 x) + (tan–1y + cot–1 y) = π … (4)

From (3) and (4), we get,

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