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The equation of state corresponding to 8 g of O2 is  (a) PV = 8RT  (b) PV = RT/4  (c) PV = RT  (d) PV = RT/2

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The equation of state corresponding to 8 g of O2 is 

(a) PV = 8RT 

(b) PV = RT/4 

(c) PV = RT 

(d) PV = RT/2

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1 Answer

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(b) PV = RT/4

8g of O2 is 1/4 of a mole of O2 , which is 32g. Thus, the required equation of state is PV = \(\frac{1}{4} RT\) .

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