(i) There are 9 boys and 4 girls. We have to select exactly 3 girls out of 4 girls and 4 boys out of 9 boys.
∴ Number of ways of selection

(ii) We have to select at least 3 girls. So the committee consists of 3 girls and 4 boys or 4 girls and 3 boys.
∴ Number of ways of selection = 4C3 × 9C4 + 4C4 × 9C3

(iii) We have to select at most 3 girls. So the committee consists of no girl and 7 boys or 1 girl and 6 boys or 2 girls and 5 boys or 3 girls and 4 boys.
∴ Number of ways of selection
