Question

7.5 g of a gas occupy 5.6 liters of volume at STP. The gas ……

(a) NO 

(b) N₂O 

(c) CO 

(d) CO₂

Answer 1

(a) NO

22.4 liters = 1 mole 

5.6 liters = 1/22.4 x 5.6

 = 0.25 mole.

NO = molar mass = 14 + 16 = 30 g = 1 mole 

N₂O = molar mass = 28 + 16 = 44g = 1 mole 

CO = molar mass = 12 + 16 = 28 g = 1 mole 

CO₂ = molar mass = 12 + 32 = 44g = 1 mole 

Among the four gases, 0.25 mole = 7.5 g is equal to NO gas.