Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
12.1k views
in Basic Concepts of Chemistry and Chemical Calculations by (44.9k points)
closed by

Calculate the empirical and molecular formula of a compound containing 32% carbon, 4% hydrogen and rest oxygen. Its vapour density is 75.

1 Answer

+1 vote
by (45.7k points)
selected by
 
Best answer

Empirical formula = C2H3O3 

Empirical formula mass = 24 + 3 + 48 = 75 

Molecular mass = 2 x (Vapour density) 

= 2 x 75 

= 150

n = (Molecular mass) / (Empirical formula mass) 

= 150/75

= 2

Molecular formula = (Empirical formula)n

Molecular formula = C2H3O3 x 2 

Molecular formula = C4H6O6

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...