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0 votes
3.3k views
in Linear Programming by (50.4k points)
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The feasible solution for a LPP is shown in Fig. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at

A. (0, 0)
B. (0, 8)
C. (5, 0)
D. (4, 10)

1 Answer

+1 vote
by (55.5k points)
selected by
 
Best answer

B. (0, 8)

Value of Z = 3x – 4y, at corner points are –

At (0, 0) = 0

At (0, 8) = -32

At (4, 10) = -28

At (6, 8) = -14

At (6, 5) = -2

At (5, 0) = 15

So, clearly minimum value is at (0, 8)

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