If A = \(\begin{bmatrix} 1 & 8 \\[0.3em]4&3\end{bmatrix}\)B = \(\begin{bmatrix} 1 & 3 \\[0.3em]7&4\end{bmatrix}\) C = \(\begin{bmatrix} -4 & 6 \\[0.3em]3&-5\end{bmatrix}\)
Prove that
(i) AB ≠ BA
(ii) A(BC) = (AB)C
(iii) A(B + C) = AB + AC
(iv) AI = IA = A