Question

A transverse wave propagating on a stretched string of linear density 3 × 10^-4 kg m^-1 is represented by the equation, y = 0.2 sin (1.5x + 60t)

Where x is in metres and t is in seconds. The tension in the string (in newtons) is:

(a) 0.24

(b) 0.48 

(c) 1.20 

(d) 1.80

Answer 1

(a) 0.48

v = \(\sqrt{\frac{T}{m}}\) = \(\frac{ω}{k}\)

⇒ T = (\(\frac{ω}{k}\))² m = \((\frac{60}{1.5})^2\) x 3 x 10^-4 

= 0.48 N