Question

Find the LCM and HCF of the pair of integers 902 and 1517 and verify that LCM x HCF = Product of two numbers.

Answer 1

Given numbers are 902 and 1517

The prime factorization of 902 and 1517 gives:

902 = 2 × 11 × 41 and 1517 = 37 × 41

Therefore, the H.C.F of these two integers = 41

Now, the L.C.M of 902 and 1517 = 2 ×

11 × 37 × 41 = 33374

Now, we have to verify

L.H.S = L.C.M × H.C.F = 33374 × 41 = 1368334

R.H.S = Product of two numbers = 902 × 1517 = 1368334

Hence, L.H.S = R.H.S

So, the product of two numbers is equal to the product of their HCF and LCM.