The function f(x) = {((x^2 - 1)/(x^3 + 1), x ≠ 1),(P, x = -1) is not defined for x = -1. The value of f(-1) so that the function extended by

Question

The function \(f(x) = \begin{cases} \frac{x^2-1}{x^3+1} & \quad \text{} x≠1 \text{ }\\ P & \quad \text{} x=-1 \text{ } \end{cases}\) is not defined for x = -1. The value of f(-1) so that the function extended by this value is continuous is ...

(a) 2/3

(b) -2/3

(c) 1

(d) 0 

Answer 1

Answer is (b) -2/3

For the function to be continuous at x = 1