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In ΔABC, P and Q are two points on AB and AC respectively such that PQ || BC and AP/PB = 2/3, then find AQ/QC.

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In ΔABC, P and Q are two points on AB and AC respectively such that PQ || BC and AP/PB = 2/3, then find AQ/QC.

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Given: PQ || BC

and AP/PB = 2/3

By Basic Proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.

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