Question

Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of 2 L at 25°C and normal pressure.

Answer 1

n = 2 moles 

V_i = 500 ml = 0.5 lit 

V_f = 2 lit 

T = 25°C = 298 K 

w = -2.303 nRT log\((\frac{V}{V_i})\) 

w = -2.303 x 2 x 8.314 x 298 x log\(\frac{2}{0.5}\) 

w = -2.303 x 2 x 8.314 x 298 x log(4) 

w = -2.303 x 2 x 8.314 x 298 x 0.6021 

w = -6871 J 

w =-6.871 kJ.

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Thnk u