Given, A = {4, 6, 8, 10}
B = {3, 4, 5, 6, 7}
f(x) = (x/2) + 1
f(4) = (4/2) + 1 = 2 + 1 = 3
f(6) = (6/2) + 1 = 3 + 1 = 4
f(8) = (8/2) + 1 = 4 + 1 = 5
f(10) = (10/2) + 1 = 5 + 1 = 6
(i) an arrow diagram
(ii) a set of ordered pairs
f = {(4, 3), (6, 4), (8, 5), (10, 6)}
(iii) a table