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Two numbers differ by 3 and their product is 504. Find the numbers.

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Let the first number be ‘X’, so the other number will be ’(X+3)’.

∵ X(X + 3) = 504

X2 + 3X– 504=0

On applying Sreedhracharya formula

X = –24 or 21.

∴ if the first number is – 24 , then the other number is – 21.

∴ if the first number is 21 , then the other number is 24.

∴ The numbers are not (21,24) & (– 21, – 24).

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