Question

A man of height 1.5 m sees the top of a tree and the angle of elevation of the top at his eye is 60°. Find the height of the tree if the distance of the man from the tree is 36 m.

Answer 1

Here distance of the man from tree is given

BC = DE = 36 m

And height of man = BD = CE =1.5 m

From the ∆ABC,

Now, height of the tree = AC + CE

= 62.35 + 1.5

= 63.85

Therefore, height of the tree is 63.85 m.