The symmetry of the problem suggests that the electric field is radial. For points r < R, consider spherical Gaussian surfaces. Then on the surface


For points, r > R, consider a spherical Gaussian surfaces’ of radius r,

The two protons must be on the opposite sides of the centre along a diameter. Suppose the protons are at a distance r from the centre.


Consider the forces on proton 1. The attractive force due to the charge distribution is

Thus, the protons must be at a distance r =R/4√8 from the centre.