Question

Two pillars of equal height are 64 m apart. The angles of elevation of their tops from any point joining their feet are respectively 30° and 60°. Find the height of the pillars.

Answer 1

Let the height of the equal pillars AB = CD = h

Given the width of the road, BD = 64m

Let BE = x. Hence, DE = 64 – x

Now, In right ΔABE, we have

⇒ h = 16√3 m

Hence, the height of the equal pillars AB = CD = 16√3m