Question

A steel wire having cross sectional area 1.5 mm² when stretched by a load produces a lateral strain 1.5 x 10^-5 . Calculate the mass attached to the wire.

(Ysteel = 2 x 10¹¹ N/m² , Poisson’s ratio σ = 0.291, g = 9.8 m/s² )

Answer 1

Given: A = 1.5 mm² = 1.5 x 10^–6 m² , lateral strain = 1.5 x 10^–5,

Y_steel = 2 x 10¹¹ N/m² ,σ = 0.291,

g = 9.8 m/s²

To find: Mass attached (M)

Formulae : a. σ = \(\frac{lateral\,strain}{longitudinal\,strain}\)

b. Y = \(\frac{longitudinal\,stress}{longitudinal\,strain}\)

Calculation: From formula,

Mass attached to the wire is 1.578 kg.