Given: Q = 0.2 μC = 0.2 x 10–6 C, A = 40 cm2 = 40 x 10–4 m2
ε0 = 8.85 x 10–12 S.I. units
To find:
a. Electric field intensity (E)
b. Mechanical force per unit area (f)
Formulae:
Calculation: Using formula (a) and (c),
a. Electric intensity is 5.649 x 106 V/m
b. Mechanical force per unit area is 141.2 N/m2