Question

A stone of mass 2 kg is whirled in a horizontal circle attached at the end of 1.5 m long string. If the string makes an angle of 30° with vertical, compute its period. (g = 9.8 m/s²)

Answer 1

Given: m = 2 kg, l = 1.5 m, θ = 30°, g = 9.8 m/s²

To find: Period (T)

Formula: T = 2π \(\sqrt{\frac{l\,cos\,θ}{g}}\)

Calculation: From formula,

∴ T = 2.2875 s

Ans: Period of revolution is 2.287 s.