Answer : (c) 50 cm

Draw the perpendicular OP and AQ as shown in the figure and join the points A and O, where O is the centre of the circle.
OA2 = (AQ2 + OQ2) = (DQ – DA)2 + (OP – QP)2
⇒ r2 = (r – 10)2 + (r – 20)2
(∵ CP = DQ = OP = OA = radius of circle = r)
⇒ r2 = r2 – 20r + 100 + r2 – 40r + 400
⇒ r2 – 60r + 500 = 0
⇒ (r – 10) (r – 50) = 0
⇒ r = 10, 50 but r > 10
∴ r = 50 cm.