Given :
\(\big[\sqrt{\frac{x}{3}}+\frac{\sqrt{3}}{x}\big]^{10}\) ,
General term :


For the term independent of x,
\(\frac{10-r}{2}\) - 2r = 0
⇒ \(\frac{10-r}{2}\) = 2r ⇒ 10 - r = 4r ⇒ 5r = 10 ⇒ r = 2
∴ T2 + 1, i.e., T3 is the term independent of x and

= \(\frac{10 \times 9}{2} \times (\frac{1}{3})^{4} \times 3\)
= \(45 \times \frac{1}{27}\)
= \(\frac{5}{3}\).