Question

In the parallelogram ABCD if ∠A = 65°, find ∠B, ∠C and ∠D.

Answer 1

Let ABCD be a parallelogram in which ∠A = 65° 

Since AD || BC we can treat AB as a transversal. So ∠A + ∠B = 180°

65° + ∠B = 180° 

∠B = 180° - 65° 

∠B = 115° 

Since the opposite angles of a parallelogram are equal, we have 

∠C = ∠A = 65° and ∠D = ∠B = 115° 

Hence, ∠B = 115°, ∠C = 65° and ∠D = 115°