Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Matrices by (46.3k points)
closed by

Given, matrix A = \(\begin{bmatrix}3\\[0.3em]2\end{bmatrix}\) and B = \(\begin{bmatrix}-2\\[0.3em]-1\end{bmatrix},\) find the matrix X such that X - A = B.

(a) \(\begin{bmatrix}0\\[0.3em]0\end{bmatrix}\)

(b) \(\begin{bmatrix}1\\[0.3em]1\end{bmatrix}\)

(c) \(\begin{bmatrix}4\\[0.3em]0\end{bmatrix}\)

(d) \(\begin{bmatrix}1\\[0.3em]-1\end{bmatrix}\)

1 Answer

+1 vote
by (49.3k points)
selected by
 
Best answer

(b) X - A = B ⇒ X = A + B

⇒ X = \(\begin{bmatrix}3\\[0.3em]2\end{bmatrix}\) + \(\begin{bmatrix}-2\\[0.3em]-1\end{bmatrix}\) = \(\begin{bmatrix}3-2\\[0.3em]2-1\end{bmatrix}\) = \(\begin{bmatrix}1\\[0.3em]1\end{bmatrix}\)

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...