Question

There are 24 balls in a pot. If 3 of them are Red, 5 of them are Blue and the remaining are Green then, what is the probability of picking out 

(i) a Blue ball, 

(ii) a Red ball and 

(iii) a Green ball?

Answer 1

n(S) = 24 

Red – n(R) = 3

Blue – n(B) = 5

Green – n(G) = 16

(i) Probability of picking a blue ball 

= \(\frac{n(B)}{n(S)}=\frac{5}{24}\)

(ii) Probability of picking a red ball 

(iii) Probability of picking a green ball