(d) 10.8
Net increase in population in a year = \(\big(4-\frac{1}{2}\big)\)% = 3\(\frac{1}{2}\) %
Let the original population of the town be 100. Then,
Population after 3 years = 100\(\big(1+\frac{3.5}{100}\big)^3\)
= \(\frac{100\times207\times 207\times207}{100\times100\times100}\) = 110.87
\(\therefore\) % increase = (110.87 – 100)% = 10.87% = 10.8%