Answer : (d) None of these
Given that,
S1 = a2 + a4 + a6 + ..... + upto 100 terms …(i)
S2 = a1 + a3 + a5 + ..... + upto 100 terms …(ii)
Let d be the common difference of the given A.P. Then,
d = a2 – a1 = a3 – a2 = a4 – a3 = …(iii)
Subtracting eqn (ii) from eqn (i), we have
S1 – S2 = (a1 – a2) + (a4 – a3) + (a6 – a5) +.... + upto 100 terms
= d + d + d + .... + upto 100 terms = 100 d
⇒ d = \(\frac{S_1 - S_2}{100}\)