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in Linear Inequations by (46.3k points)
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Evaluate :

\(\frac{(0.43)^3 + (1.47)^3 + (1.1)^3 - 3 \times 0.43 \times 1.47 \times 1.1}{(0.43)^2 + (1.47)^2 + (1.1)^2 - 0.43 \times1.43-0.43\times1.1-1.47\times1.1}\)

(a) 1.90 

(b) 2.87 

(c) 3

(d) 3.47

1 Answer

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Best answer

(c) 3

Reqd. exp. is of type \(\frac{a^3 + b^3 + c^3 -3abc}{a^2 + b^2 + c^2 - ab -bc-ca}\)

You know that (a + b + c)(a2 + b2 + c2 - ab - bc - ca) = a3 + b3 + c3 - 3 abc

⇒ a + b + c = \(\frac{a^3 + b^3 + c^3 -3abc}{a^2 + b^2 + c^2 - ab -bc-ca}\)

∴ Reqd. exp. = 0.43 + 1.47 + 1.1 = 3.

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