√((0.798)^2 + 0.404 x 0.798 + (0.202)^2) + 1 is equal to

Question

\(\sqrt{(0.798)^2 + 0.404\times0.798 + (0.202)^2} + 1\) is equal to

(a) 0 

(b) 2

(c) 1.596 

(d) 0.404

Answer 1

(b) 2

 \(\sqrt{(0.798)^2 + 0.404\times0.798 + (0.202)^2} + 1\) 

= \(\sqrt{(0.798)^2 + 2\times0.202\times0.798 + (0.202)^2} + 1\)

= \(\sqrt{(0.798 +0.202)^2} + 1\) = √1 + 1 = 1 + 1 = 2.