The value of (sin 19°)/(cos 71°)+(cos 73°)/(sin 17°) is equal to :

Question

The value of \(\frac{sin\,19°}{cos\,71°}+\frac{cos\,73°}{sin\,17°}\) is equal to :

(a) 0 

(b) 1 

(c) 2 

(d) \(\frac12\)

Answer 1

(c) 2

Given exp.

= \(\frac{sin(90°-71°)}{cos\,71°}+\frac{cox\,73°}{sin(90°-73°)}\)

= \(\frac{cos\,71°}{cos\,71°}+\frac{cos\,73°}{cos\,73°}\)            (∵sin (90° – θ) = cos θ)

= 1 + 1 = 2.