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in Algebraic Expressions by (49.3k points)
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The factors of 9a2 - 6√5a + 5 are

(a) (3a + √5) (3a - √5)

(b) (3a - 5) (3a - 5) 

(c) (3a - √5) (3a - √5)

(d) (3a + √5) (3a - 5)

1 Answer

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Best answer

(c) (3a - √5) (3a - √5)

9a2 - 6√5a + 5

= (3a)2 - 2 x 3a x √5 + (√5)2

= (3a - √5)2 = (3a - √5) (3a - √5)

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