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The taxi charges in a city comprise of a fixed charge of Rs 100 for 5 kms and Rs 16 per km for ever additional km. If the amount paid at the end of the trip was Rs 740, find the distance traveled.

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Let the distance travelled by taxi be ‘x’ km 

For the first 5 km the charge = Rs 100 

For additional kms the charge = Rs 16(x – 5) 

∴ For x kms the charge = 100 + 16(x – 5) 

Amount paid = Rs 740 

∴ 100 + 16(x – 5) = 740 

100 + 16(x – 5) – 100 = 740- 100 

16(x – 5) = 640

\(\frac{16(x-5)}{16}=\frac{640}{16}\)

x – 5 = 40 

x – 5 + 5 = 45 + 5 

x = 45 

x = 45 km 

∴ Total distance travelled = 45 km

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