A coin is tossed 6 times. In how many different ways can we obtain 4 heads and 2 tails?

Whether we toss a coin 6 times or toss 6 coins at a time, the number of arrangements will be the same.

∴ The number of arrangements of 4 heads and 2 tails out of 6 is \(\frac{6!}{4!2!}=15.\)

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