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If tan \(\bigg(\frac{π}{4}+θ\bigg)\) + tan \(\bigg(\frac{π}{4}-θ\bigg)\) = p sec 2θ, then find the value of p.

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 tan \(\bigg(\frac{π}{4}+θ\bigg)\) + tan \(\bigg(\frac{π}{4}-θ\bigg)\) = p sec 2θ

⇒ 2 sec 2θ = p sec 2θ ⇒ p = 2.

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