(i) ab + ba
a = 3 and b = 2
We get 32 + 23 = (3 x 3) + (2 x 2 x 2)
= 9 + 8
= 17
(ii) (aa – bb)
Substituting a = 3 and b = 2
We get 32 – 22 = (3 x 3 x 3) – (2 x 2)
= 27 – 4
= 23
(iii) (a + b)b
Substituting a = 3 and b = 2
We get (3 + 2)2 = 52
= 5 x 5
= 25
(iv) (a – b)a
Substituting a = 3 and b = 2
We get (3 – 2)3 = 13
= 1 x 1 x 1
= 1