Question

Three consecutive integers, when taken in increasing order and multiplied by 2, 3 and 4 respectively, total up to 74. Find the three numbers.

Answer 1

Let the 3 consecutive integers be ‘x’, ’x + 1 & ‘x + 2’
Given that when multiplied by 2, 3 & 4 respectively & added up, we get 74

Simplifying the equation, we get

2x + 3x + 3 + 4x + 8 = 74

9x + 11 = 74

9x = 63 ⇒ x = 63/9 = 7

First number = 7

Second numbers = x + 1

Third numbers = x + 2

∴ The numbers are 7, 8 & 9