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Mayan travelled 28 km due north and then 21 km due east. What is the least distance that he could have travelled from his starting point?

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Mayan travelled 28 km due north and then 21 km due east. What is the least distance that he could have travelled from his starting point?

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1 Answer

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Best answer

From the figure AC is to be found.

By using Pythagoras theorem,

AC2 = AB2 + BC2

= 282 + 212 = 784 + 441 = 1225 = 352

∴ AC = 35 km

This is the least distance that he could have travelled from his starting point.

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