\( \operatorname{Lim}_{n \rightarrow \infty} \frac{\left(1^{2022}+2^{2022}+3^{2022}+\ldots n^{2022}\right) n}{1^{2023}+2^{2023}+

\( \operatorname{Lim}_{n \rightarrow \infty} \frac{\left(1^{2022}+2^{2022}+3^{2022}+\ldots n^{2022}\right) n}{1^{2023}+2^{2023}+\ldots n^{2023}} \) is equal to \( \frac{a}{b} \) where \( a \) and \( b \) are coprime then \( a+b= \)

answer is 4047

\( \operatorname{Lim}_{n \rightarrow \infty} \frac{\left(1^{2022}+2^{2022}+3^{2022}+\ldots n^{2022}\right) n}{1^{2023}+2^{2023}+\ldots n^{2023}} \) is equal to \( \frac{a}{b} \) where \( a \) and \( b \) are coprime then \( a+b= \)

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