Question

Which of the following compounds will not exist as resonance hybrid? Give reason for your answer.

(i) CH₃OH 

(ii) R-CONH₂ 

(iii) CH₃CH = CHCH₂NH₂

Answer 1

(i) CH₃OH does not contain pi-electrons; hence, it cannot exist as resonance hybrid.

(ii) Due to the presence of pi-electrons in C = O bond and lone pair of electrons on N amide can be represented by the following resonating structures:

(iii) CH₃CH = CHCH₂NH₂: Since lone pair of electrons on nitrogen atom is not conjugated with the pi -electrons, therefore, resonance is not possible.