Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
9.5k views
in Straight Lines by (27.7k points)
closed by

Find the equation of the perpendicular bisector of the line segment joining the points A(2, 3) and B(6, – 5).

1 Answer

+1 vote
by (25.7k points)
selected by
 
Best answer

The mid-point of A(2, 3) and B(6, – 5), 

= \((\frac{2+6}{2},\frac{3-5}{2})=(4, -1)\) 

And slope of AB, m =\(\frac{-5-3}{6-2}=-2\)

∴ Slope of the Perpendicular bisector of 

   AB, m’ = \(\frac{-1}{m}=\frac{1}{2}\)

Since the bisector passes through (4, – 1), so the equation of the Perpendicular bisector is 

Y – (– 1) = \(\frac{1}{2}\)( – 4) 

⇒ y + 1 = \(\frac{1}{2}\)(x − 4) 

⇒ x – 4 = 2y + 2 

⇒ x – 2y – 6 = 0, is the required equation.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...